Flexural design support B

Support B (and D)

At centerline of support

M = 657.4 kNm At face of support

MEd = 657.4 - 0.2 x 517.9 + 0.202 x 128.5 / 2 = 657.4 - 101.0 = 556.4 kNm

= MEd / bwd2fCk where bw — 2000 mm d — 300 - 25 cover - 12 fabric - 8 link - 16 bar - 25 / 2 bar — 226 mm

Figure 4.20 Section at solid/rib intersection

Figure 4.20 Section at solid/rib intersection

K = 556.4 x 106 / (2000 x 2262 x 35) = 0.156 By inspection, K < K'

.'. No compression steel required z = (226 / 2)[1 + (1 - 3.53 K')05] = (226 / 2)[1 + (1 - 3.53 x 0.156)05] = (226 / 2) (1 + 0.67) < 0.95d = 189 mm

<Appendix A1> <Concise EC2 Table 15.4>

<9.2.1.2(2), Fig. 9.1> <5.3.2.1, Fig. 5.3>

**** Both Aeprov / Asreq and any adjustment to N obtained from Exp. (7.16a) or Exp. (7.16b) is restricted to 1.5 by Note 5 to Table NA.5 in the UK NA.

where bf = (0.2b, + 0.1/0) < 0.2 /0 < b, where b, referring to Figure 3.9

= (7500 - 1000 - 550) / 2 = 2975 mm /0 = 0.15 x (/, + /2) = 0.15 x (7500 + 7500) = 2250 mm beff1 = (0.2 x 2975 + 0.1 x 2250 < 0.2 x 2250 < 2975 = 820 < 450 < 2975 = 450 mm bw = 2000 mm be

: 450 mm as before

Check cracking

Spacing = 2900 - 2 x (25 - 10 - 25 / 2) / (14 - 1) = 216 mm

= (fyk / Ys) (Aare, / A6.prov) (SLS loads/ULS loads) (1 / S) = 4348 x (6770 / 6874) [ (47.8 + 0.3 x 458) /

(125 x 47.8 + 15 x 45.8) x (1 /0.85) = 434.8 x 0.98 x 0.48 x 1.18 = 241 MPa As loading is the cause of cracking satisfy either Table 7.2N or Table 7.3N For wk = 0.4 and crs = 240 MPa max. spacing = 250 mm .'. OK

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