Lxn

Minimum steel governs.

Critical shear section at distance d from face of column Column B interior side

= 1717 - 0.675 x 657 = 1273 kN = rRd k( 1.2 + 40p,)bwd = 0.34 N/mm2 k = 1.6 - d < 1.0 = 1.0 p, = 0.00476 Ensure bars are continued sufficiently.

Sd Rd1

Therefore shear reinforcement required. Shear capacity with links

Therefore

cd wd Rd1 wd wd

316 kN

Eqn 4.23

f ri ywd

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