M

+ (-j-) ^Sd(cote - cota) = 1091 + 606 = 1697 kN Eqn 4.30

This compares with 7"d = 1495 kN using the standard method. Note:

Although not permitted by the NAD, values of cote up to 2.5 are given in EC2.

A check on shear reinforcement using cote = 2.5 is now given to illustrate the effect of increasing values of e on shear and tension reinforcement.

808.5 x 103

S ywd cote 810 x 217A x 25

Check maximum spacing of links Pw = 0.005

Maximum spacing for crack control = 250 mm OK

| Use R12 links @ 225 mm crs. (4 legs) Check additional force in tension reinforcement.

Table 4.13 Eqn 5.18

This compares with 7"d = 1495 kN using the standard method.

Sd Rd1

Since only minimum shear reinforcement is required this case is identical to that shown in Section 3.2.2.1.2.

520 x 103

810 x 217.4 x 1.5 Try R12 links @ 225 mm crs. (4 legs), A Is = 2.01 mm2/mm

From Section 3.2.2.2.1 spacing is satisfactory.

As in Section 3.2.2.1.3, check the point at which the shear requirement is satisfied by R12 @ 200 mm crs. (4 legs).

sw s

2.26 mrrr/mm

0 0

Post a comment