N

Fv = E all vertical loads at given level (under service condition)

n = Number of columns

Consider a simple analytical model of the top floor to determine columns concerned as shown in Figure 4.24.

Figure 4.24 Load arrangement at third floor = 11.4 kN/m2 x loaded width

= 11.4 x 5.2 (determined in Section 4.2.1.1) = 59.3 kN/m = 3 x 59.3 X 4.25/8 + 50 = 145 kN = 5 x 59.3 x 4.25/8 + (59.3 x 5.2/2) = 312 kN = 59.3 x 5.2 = 308 kN 100 + (18.9 x 59.3)

Figure 4.24 Load arrangement at third floor = 11.4 kN/m2 x loaded width

= 11.4 x 5.2 (determined in Section 4.2.1.1) = 59.3 kN/m = 3 x 59.3 X 4.25/8 + 50 = 145 kN = 5 x 59.3 x 4.25/8 + (59.3 x 5.2/2) = 312 kN = 59.3 x 5.2 = 308 kN 100 + (18.9 x 59.3)

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