Dx from to

40 kip-ft dM

40 kip-ft dM

varies

Reactions are determined from the equilibrium equations

Shear are determined next.

(11)(4) + (8)(1O) + (4)(2)(14 + 2) - RPy (18) = O ^ RFy =14 k RAy - 11 - 8 - (4)(2) + 14 = O ^ RAy = 13 k

1. At A the shear is equal to the reaction and is positive.

2. At B the shear drops (negative load) by 11 k to 2 k.

4. It stays constant up to D and then it decreases (constant negative slope since the load is uniform and negative) by 2 k per linear foot up to —14 k.

5. As a check, —14 k is also the reaction previously determined at F.

Moment is determined last:

1. The moment at A is zero (hinge support).

2. The change in moment between A and B is equal to the area under the corresponding shear diagram, or AMB-A = (13)(4) = 52.

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