The hydrodynamic pressure for a harmonic ground excitation of ug = e would be:
iwt p(x,y,t) = — V -, exp -x\ X2m - ^ cos Xmy elwt n m-i (2m -1)^ - v v CV
It can be seen that as x ^ to the pressure does not approach zero if Am < c which was the fourth boundary condition imposed in Westergaard solution. To compare the above solution with Westergaard's solution, we can consider the real part of the ground motion as well as coefficient ag (ug = ag cos(^)).The Solution in this case consist of the real part of the pressure solution (equation 2.41) and would be as:
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