Info

Design angle of shearing resistance ^ = tan tan w v Y{P J

Design effective cohesion c'd =-

Partial factors from Sets fR1 ^

vR1 J

v1 J

Design shear resistance trj =

yRe v22.9 j kPa

Verification of strength against sliding

Degree of utilization is

Degree of utilization is

The design is unacceptable if the degree of utilization is > 100%

The design is unacceptable if the degree of utilization is > 100%

Design Approach 2

Actions and effects

Characteristic values = same as for Design Approach 1 Partial factor from Set A1: yg = 1.35

Design normal stress ct' nd = yg fav x CT'nk = 57.2 kPa© Design shear thrust t^ = Yq x T^k = 31.8 kPa

Material properties and resistance

Characteristic resistance = same as for Design Approach 1

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