Info

r 1 ^

s

VM2 y

: yp =

.125 y

v1.25 y

Design angle of shearing resistance <d = tan tan

Design effective cohesion c'j =-=

Partial factors from Set vR1 J

v1 J

Design shear resistance is tr^

v31.8 j kPa

Verification of strength against sliding

Degree of utilization is

Degree of utilization is

The design is unacceptable if degree of utilization is > 100%

The design is unacceptable if degree of utilization is > 100%

Design Approach 2

Actions and effects

Characteristic values = same as for Design Approach 1 Partial factor from Set A1: yg = 1.35 and yg fav = 1

Design normal stress and = yg fav x CTnk = ®1 kPa© Design shear stress t^ = Yg x T|=k = 36.5 kPa

Material properties and resistance

Characteristic resistance = same as for Design Approach 1

Design angle of shearing resistance <d = tan tan w v Y< J

Design effective cohesion c'd --- 2kPa

Partial factor on sliding resistance from Set R2: YRe = 1.1 © c'd + °ndx tan(<d)

Shear resistance t

36.2 kPa yRe

0 0

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