d2M ,

d2M' dx1

The general solution will be of the form

Now for zero transverse load (or for any concentrated load) (d2M'/dx2) is zero, the particular solution is also zero, and the solution for the above expression is in the form

Thus, for an eccentrically loaded strut (Smith-Southwell):

Therefore substituting, M = Pe sec — cos nx and

as before

For a central concentrated load (see Fig. 2.12)

- 0 and the particular solution = 0

Shear force =

dx and

0 0

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