where d is the depth of the elastic core in centimetres,

8.8 = 12 - d2 d2 = 3.2 and d = 1.79 cm depth of yielding = \(D - d) = 20 - 17.9) = 1.05 mm

(c) With the central load at 1650 N the yielding will have spread from the centre as shown in Fig. 3.37. At the extremity of the yielded region, a distance x from each end of the beam, the section will just have yielded at the extreme surface fibres, i.e. the moment carried at this section will be the maximum elastic moment and given by eqn. (3.1) - see part (a) above.

0 0

Post a comment