T

kidb2

0.333 x 123.8 x 10"3 x (2 x 10"8)2 = 6.06 x 106T

i.e. splitting the tube along its length has reduced the stiffness by a factor of approximately 300, the maximum stress increasing by approximately 30 times.

(c) Rectangular bar

Area of hollow tube = area of bar

= n x (20 x 10"3)2 4b2 = 87T x 10"4 b2 =2tz x 10"4 b = 2.5 x 10"2 m = 25 mm d = 4b = 100 mm d/b ratio = 4 Therefore from eqn. (5.2), ki = 0.282 and k2 = 0.281

L k2db3G T

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