Limiting the axial resistance to 25% of the Johansen yield equation:

F 1v.Rk.b = (1.25) • 2.3 • VMy.Rk • fh.a.k • d Fv.Rk.b = 1.19 x 104N

The characteristic lateral resistance per Fv.Rk = min(Fv Rk.a, F 1v Rk.b)

i.e. failure mode (I) - bearing in timber

The design load carrying capacity per Fv.Rd =-

bolt per shear plane, Fv.Rd: mcom^tion

The design load on the bolt per shear Fd = 2.71 x 103 N plane, Fd:

The design load is less than the capacity of the bolt; therefore OK

Check the capacity of the row of bolts subjected to the maximum forces parallel to the grain i.e. the bolts in the row positioned 85 mm above the centroid. (NB: No need to check rows perpendicular to grain as there is no strength reduction in that direction.)

The characteristic load-carrying capacity per shear plane per bolt based on failure mode I, F 1v.Rk.a

(from consideration of the strength equations this will still be the failure condition)

F 1v

Number of bolts per shear plane in the nb = 3 row, nb:

Effective number of bolts per shear plane in the row, nef (equation (10.45); EC5, equation (8.34))

(The equation incorporates dimension factors for Mathcad.)

F 1v

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