## Info

Shear plane 2 strength assessment (based on 2,3,2 configuration):

Double shear joint formed from members 2,3,2. For a timber-to-timber joint with a bolt in double shear, the characteristic lateral resistance per shear plane is the smallest value of equations (10.7)-(10.10) in Table 10.2 (EC5, equations (8.7)), where:

Ratio of the embedment strength of P3.2 = ~--P3.2 = 1.4

Failure mode (g):

Fv.Rk.1.a = fh.0.2.3.a.k ' t2 ■ d Fv.Rk.1.a = 9.91 kN

Failure mode (h):

Fv.Rk.2.a = 0.5 ■ fh.0.3.2.a.k ' t3 ■ d Fv.Rk.2.a = 9.7kN

Failure modes (j) and (k) are not compatible with FV.Rk.1.2 and are not considered (10.7 (EC5, 8.1.3(2)))

Minimum value for Fv.Rk.2.3 = min(Fv.Rk.1.a, Fv.Rk.2.a) Fv.Rk.2.3 = 9.7kN

Shear plane 2 strength assessment (based on 3,2,3 configuration):

Double shear joint formed from members 3,2,3. For a timber-to-timber joint with a bolt in double shear, the characteristic lateral resistance per shear plane is the smallest value of equations (10.7)-(10.10) in Table 10.2 (EC5, equations (8.7)), where:

Ratio of the embedment strength of P2.3 = ~--P2.3 = 0.72

Failure mode (g): Fv.Rk.Lb = fh.e.3.2.b.k ■ t3 ■ d Fv.Rk.1.b = 19.4kN

Failure mode (h): Fv.Rk.2.b = 0.5 ■ fh.e.2.3.b.k ■ t2 ■ d Fv.Rk.2.b = 4.96 kN

Failure modes (j) and (k) are not compatible with FV.Rk.1.2 and not considered (10.7 (EC5, 8.1.3(2)))

Minimum value for the shear plane Fv.Rk.3.2 = min(Fv Rk1.b, Fv.Rk.2.b)

Strength of shear plane 2 (based on minimum value for 2,3,2 and 3,2,3 configurations):

Minimum characteristic strength of Fv.Rk.2.3.f = min(Fv.Rk.2.3, Fv Rk.3.2) shear plane 2, Fv.Rk.2.3.f

Design force in shear plane 2 Fv.sp.2 = 1.44 x 103 N

Design capacity of shear plane 2 Fv.R.d.sp.2 = kmod.med ^ Fv.Rk.2.3.f yM. connection

Design capacity of shear plane 2 exceeds the design force in shear plane 2; therefore OK.

### 6. Splitting capacity of timber

As the direction of shear plane 1 force relative to member 1 and of shear plane 2 force relative on member 3 is parallel to the grain of these members, timber splitting will not be relevant to these members.

Splitting strength will, however, need to be investigated for member 2 in joint 1,2,1 (and member 2 in joint 3,2,3, which is subjected to the same loading condition):

Splitting force in member 2 for each joint set-up, Fv.Ed

Design splitting capacity of member 2, F90.Rd (Equation 10.41(c) (EC5, 8.1.4))

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